Sequence and Series Questions and Answers Part-4

1. If the ratio of sums to n terms of two A.P’s is (5n + 3) :(3n+4) then the ratio of their 17th terms is
a) 172 : 99
b) 168 : 103
c) 175 : 99
d) 171 : 103

Answer: b
Explanation: Let two A.P.’s be
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2. If \[H_{1},H_{2},....,H_{n}\]   are n harmonic means between a and \[b\left(\neq a\right)\]  , then value of \[\frac{H_{1}+a}{H_{1}-a}+\frac{H_{n}+b}{H_{n}-b}\]    is equal to
a) n + 1
b) n - 1
c) 2n
d) 2n + 3

Answer: c
Explanation: As a, H1, H2, .... , Hn, b are in H.P
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3. Let \[a_{1},a_{2},....,a_{n}\]    be n positive real numbers such that \[a_{1}a_{2}....a_{n}=c\]    , where c number. The expression \[a_{1}+2a_{2}+3a_{3}+....+na_{n}\]     cannot be less than
a) n! c
b) \[n\left(n! c\right)^{1/n}\]
c) \[C^{1/n}\]
d) \[\left(2n\right)C^{1/n}\]

Answer: b
Explanation:
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4. The sum upto (2n + 1) terms of the series \[a^{2}-\left(a+d\right)^{2}+\left(a+2d\right)^{2}-\left(a+3d\right)^{2}+....\]
is
a) \[a^{2}+3nd ^{2}\]
b) \[a^{2}+2nad +n\left(n-1\right)d^{2}\]
c) \[a^{2}+3nad +n\left(n-1\right)d^{2}\]
d) \[a^{2}+2nad +n\left(2n+1\right)d^{2}\]

Answer: d
Explanation: We can write the sum upto (2n + 1) terms as
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5. Value of y=\[(0.64)^{\log_{0.25}\left(\frac{1}{3}+\frac{1}{3^{2}}+\frac{1}{3^{3}}+.... \infty\right)} \]
is
a) 0.9
b) 0.8
c) 0.6
d) 0.25

Answer: b
Explanation:
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6. Let \[ax^{2}+\frac{b}{x}\geq c\]   for all positive x, where a > 0 and b>0. The value of the expression \[27 ab^{2}\] cannot be less than
a) \[4c^{3}\]
b) \[4c^{2}\]
c) \[8c^{3}\]
d) \[c^{3}\]

Answer: a
Explanation: As A.M. ≥ G.M., we get
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7.Let \[b_{i}>1\]  for i = 1, 2, …, 101. Suppose \[\log_{e}b_{1},\log_{e}b_{2},.....,\log_{e}b_{101}\]      are in Arithmetic Progression (A.P.) with the common difference \[log_{e} 2\] . Suppose \[a_{1},a_{2},....,a_{101}\]    are in A.P. such that \[a_{1}=b_{1}\]  and \[a_{51}=b_{51}\]  . If \[t= b_{1}+b_{2}+....+b_{51}\]     and \[S= a_{1}+a_{2}+....+a_{51}\]    , then
a) \[S> t\]   and \[a_{101}>b_{101}\]
b) \[S> t\]   and \[a_{101}< b_{101}\]
c) \[S< t\]   and \[a_{101}>b_{101}\]
d) \[S< t\]   and \[a_{101}< b_{101}\]

Answer: d
Explanation: logeb1, logeb2, .…, logeb101 are in A.P. with
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8.If \[S_{n}=\sum_{r=1}^{n}t_{r}=\frac{1}{6}n\left(2n^{2}+9n+13\right)\]      , then \[\sum_{r=1}^{n}\sqrt{t_{r}}\]   equals
a) \[\frac{1}{2}n\left(n+1\right)\]
b) \[\frac{1}{2}n\left(n+2\right)\]
c) \[\frac{1}{2}n\left(n+3\right)\]
d) \[\frac{1}{2}n\left(n+5\right)\]

Answer: c
Explanation:
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9. If 0< \[\theta\] , \[\phi < \pi/2\]   and \[x=\sum_{n=0}^{\infty} \sin^{2n}\theta,y=\sum_{n=0}^{\infty} \cos^{2n}\phi,\]
and \[z=\sum_{n=0}^{\infty} \cos^{n}\left(\theta+\phi\right)\cos^{n}\left(\theta-\phi\right)\]
a) xyz + 1 = yz – zx
b) xyz – 1 = yz + zx
c) xyz – xy = yz – zx
d) xyz + 1 = yz + zx

Answer: c
Explanation:
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10. If \[a_{1},a_{2},....,a_{n}\]    are in A.P. with common difference d \[\neq\] 0, then sum of the series \[\sin d\left[\sec a_{1}\sec a_{2}+\sec a_{2}\sec a_{3}+....+\sec a_{n-1}\sec a_{n}\right]\]
is
a) \[\tan a_{n}-\tan a_{1}\]
b) \[\cot a_{n}-\cot a_{1}\]
c) \[\sec a_{n}-\sec a_{1}\]
d) cosec an - cosec a1

Answer: a
Explanation:
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