1. Kinetic theory of gases was put forward by

a) Einstein

b) Newton

c) Maxwell

d) Raman

Explanation: Kinetic theory of gases was put forward by Maxwell

2. One litre of Helium gas at a pressure 76 cm of Hg and temperature \[27^{\circ}\] is heated till its pressure and volume are doubled. The final temperature
attained by the gas is

a) \[927^{\circ}C\]

b) \[900^{\circ}C\]

c) \[627^{\circ}C\]

d) \[327^{\circ}C\]

Explanation:

3. A flask is filled with 13 gm of an ideal gas at \[27^{\circ} C\] and its temperature is raised to \[52^{\circ} C\] . The mass of the gas that has to be released to maintain the
temperature of the gas in the flask at \[52^{\circ} C\] and the pressure remaining the same is

a) 2.5 g

b) 2.0 g

c) 1.5 g

d) 1.0 g

Explanation: Since P, V , M and R are constants,

m

_{1}T

_{1}= m

_{2}T

_{2}

13×300=m

_{2}×325

m

_{2}=12gm

Hence mass to be removed = 13-12= 1gm

4. The molecular weight of a gas is 44. The volume occupied by 2.2 g of this gas at \[0^{\circ} C\] and 2 atm.
pressure will be

a) 0.56 litre

b) 1.2 litres

c) 2.4 litres

d) 5.6 litres

Explanation:

5. A gas at 27^{0}C temperature and 30 atmospheric pressure is allowed to expand to the atmospheric pressure. If the volume becomes 10 times its initial volume, then the final temperature
becomes

a) \[100^{\circ}C\]

b) \[173^{\circ}C\]

c) \[273^{\circ}C\]

d) \[-173^{\circ}C\]

Explanation:

6. When volume of system is increased two times and temperature is decreased half of its initial temperature, then pressure becomes

a) 2 times

b) 4 times

c) \[\frac{1}{4} times\]

d) \[\frac{1}{2} times\]

Explanation:

7. A balloon contains 1500 m^{3} of helium at \[27^{\circ} C\] and 4 atmospheric pressure. The value of helium at
\[-3^{\circ} C\] temperature and 2 atmospheric pressure will be

a) 1500 \[m^{3} \]

b) 1700 \[m^{3} \]

c) 1900 \[m^{3} \]

d) 2700 \[m^{3} \]

Explanation:

8.A gas at 27°C has a volume V and pressure P. On heating its pressure is doubled and volume becomes three times. The resulting temperature
of the gas will be

a) \[1800^{\circ}C\]

b) \[162^{\circ}C\]

c) \[1527^{\circ}C\]

d) \[600^{\circ}C\]

Explanation:

9. The equation of state corresponding to 8 g of \[O_{2}\] is

a) PV = 8RT

b) PV = RT/4

c) PV = RT

d) PV = RT/2

Explanation:

10. The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be

a) PV = (5 / 32)RT

b) PV = 5RT

c) PV = (5 / 2)RT

d) PV = (5 / 16)RT

Explanation: