Chemical Bonding and Molecular Structure Questions and Answers Part-5

1. Which one of the following compounds has sp2 hybridisation?
a) \[CO_{2}\]
b) \[SO_{2}\]
c) \[N_{2}O\]
d) CO

Answer: b
Explanation: SO2 has sp2 hybridisation.

2. The \[AsF_{5}\] molecule is trigonal bipyramidal. The hybrid orbitals used by the As atoms for bonding are :
a) \[d_{x^{2}-y^{2}},d_z^2,s,p_{x},p_{y},p_{z}\]
b) \[d_{xy},s,p_{x},p_{y},p_{z}\]
c) \[s,p_{x},p_{y},p_{z},d_z^2\]
d) \[d_{x^{2}-y^{2}},s,p_{x},p_{y}\]

Answer: c
Explanation: AsF5 is trigonal bipyramidal and sp3d hybridised.

3. The hybridization of S atom in \[SO_4^{2-}\] is
a) sp
b) \[sp^{2}\]
c) \[sp^{3}\]
d) \[sp^{3}d\]

Answer: c
Explanation: \[sp^{3}\]

4. Which of the following will be octahedral ?
a) \[SF_{6}\]
b) \[BF_4^-\]
c) \[PCI_{5}\]
d) \[BO_3^{3-}\]

Answer: a
Explanation: \[SF_{6}\] is octahedral

5. The hybridization of atomic orbitals of nitrogen in \[NO_2^+\], \[NO_2^-\] and \[NH_4^+\] are
a) \[sp^{2}\], \[sp^{3}\] and \[sp^{2}\] respectively
b) sp, \[sp^{2}\] and \[sp^{3}\] respectively
c) \[sp^{2}\], sp and \[sp^{3}\] respectively
d) \[sp^{2}\], \[sp^{3}\] and sp respectivley

Answer: b
Explanation: \[NO_2^+\] = ½ [5 + O + O –1] = 2 sp; \[NO_2^-\] = ½ [5 + 0 + 1 –0] = 3 sp2; \[NH_4^+\] = ½ [5 + 4 + 0 - 1] = 4 sp3

6. The shape of gaseous \[SnCI_{2}\]   is
a) tetrahedral
b) linear
c) angular
d) t-shape

Answer: c
Explanation: The shape of gaseous \[SnCI_{2}\]  is angular

7. Which of the following molecule is linear ?
a) \[SO_{2}\]
b) \[NO_2^+\]
c) \[NO_2^-\]
d) \[SCI_{2}\]

Answer: b
Explanation: \[NO_2^+\] has sp hybridisation hence linear

8. Each carbon in carbon suboxide (\[C_{3}\]\[O_{2}\]) is
a) \[sp^{2}\] - hybridized
b) \[sp^{3}\] - hybridized
c) sp - hybridized
d) \[sp^{2}\] - hybridized but linked with one co-ordinate bond

Answer: c
Explanation: O = C = C = C = O is sp hybridised

9. In \[XeF_{2}\] , \[XeF_{4}\] and \[XeF_{6}\] , the number of lone pairs on Xe are respectively
a) 2,3,1
b) 1,2,3
c) 4,1,2
d) 3,2,1

Answer: d
Explanation: In XeF2 Total number of valence electrons of Xe = 8, two electrons shared with 2F atoms, 6 electrons left hence 3 lone pairs, in XeF4 4 shared with 4 F atoms 4 left hence 2 lone pairs; in XeF6 6 shared with 6 F atoms 2 left hence 1 lone pair.

10. A square planar complex is formed by hybridisation of which atomic orbitals ?
a) \[s,p_{x},p_{y},d_{yz}\]
b) \[s,p_{x},p_{y},d_{x^{2}-y^{2}}\]
c) \[s,p_{x},p_{y},d_{z}\]
d) \[s,p_{x},p_{z},d_{xy}\]

Answer: b
Explanation: dsp2 hybridisation involves \[d_{x^{2}-y^{2}}\]