Units and Measurement Questions and Answers Part-12

1. Dimensional formula for latent heat is
a) \[M^{0}L^{2}T^{-2}\]
b) \[MLT^{-2}\]
c) \[ML^{2}T^{-2}\]
d) \[ML^{2}T^{-1}\]

Answer: a
Explanation:
q111

2. Dimensional formula for volume elasticity is
a) \[M^{1}L^{-2}T^{-2}\]
b) \[M^{1}L^{-3}T^{-2}\]
c) \[M^{1}L^{2}T^{-2}\]
d) \[M^{1}L^{-1}T^{-2}\]

Answer: d
Explanation:
q112

3. The dimensional formula of angular velocity is
a) \[ MLT^{-1}\]
b) \[ M^{0}L^{0}T^{-1}\]
c) \[ M^{0}L^{0}T^{1}\]
d) \[ ML^{0}T^{-2}\]

Answer: b
Explanation:
q113

4. The dimensions of power are
a) \[ M^{1}L^{2}T^{-3}\]
b) \[ M^{2}L^{1}T^{-2}\]
c) \[ M^{1}L^{2}T^{-1}\]
d) \[ M^{1}L^{1}T^{-2}\]

Answer: a
Explanation:
q114

5. The dimensions of couple are
a) \[ ML^{2}T^{-2}\]
b) \[ MLT^{-2}\]
c) \[ ML^{-1}T^{-3}\]
d) \[ ML^{-2}T^{-2}\]

Answer: a
Explanation: Couple = Force * Arm length = [MLT-2][L] = [ML2T-2]

6. Dimensional formula for angular momentum is
a) \[ ML^{2}T^{-2}\]
b) \[ ML^{2}T^{-1}\]
c) \[ MLT^{-1}\]
d) \[ M^{0}L^{-2}T^{-2}\]

Answer: b
Explanation:
q116

7. The dimensional formula for impulse is
a) \[ MLT^{-2}\]
b) \[ MLT^{-1}\]
c) \[ ML^{-2}T^{-1}\]
d) \[ M^{-2}LT^{-1}\]

Answer: b
Explanation:
q117

8. The dimensional formula for the modulus of rigidity is
a) \[ M^{2}LT^{-2}\]
b) \[ ML^{-1}T^{-3}\]
c) \[ ML^{-2}T^{-2}\]
d) \[ ML^{-1}T^{-2}\]

Answer: d
Explanation:
q118

9. The dimensional formula for r.m.s (root mean square) velocity is
a) \[ M^{0}LT^{-1}\]
b) \[ M^{0}L^{0}T^{-2}\]
c) \[ M^{0}L^{0}T^{-1}\]
d) \[ MLT^{-3}\]

Answer: a
Explanation: \[ M^{0}LT^{-1}\]

10. The dimensional formula for Planck's constant (h) is
a) \[ML^{-2}T^{-3}\]
b) \[ML^{2}T^{-2}\]
c) \[ML^{2}T^{-1}\]
d) \[ML^{-2}T^{-2}\]

Answer: c
Explanation:
q120