The relationship between e, S and na is ______
a) \(n_a=e*\frac{1+S}{1+e}\)
b) \(n_a=e*\frac{1-S}{1-e}\)
c) \(n_a=\frac{1-S}{1+e}\)
d) \(n_a=e*\frac{1-S}{1+e}\)
Answer: d
Explanation: The percentage air voids is given by,
\(n_a=\frac{V_a}{V}\)
Va = Vv – Vw = e – ew
And V = Vs+Vv = 1+e
na=\(\frac{e-e_w}{1+e}\)
Since ew = eS
\(n_a=e*\frac{1-S}{1+e}\).
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