The relationship between γ_sat, G and e is _______
a) \(γ_{sat}=\frac{(G*e) γ_w}{(1+e)}\)
b) \(γ_{sat}=\frac{(G-e) γ_w}{(1+e)}\)
c) \(γ_{sat}=\frac{(G+e) γ_w}{(1+e)}\)
d) \(γ_{sat}=\frac{(G+e)}{(1+e)}\)

Answer: c
Explanation: The saturated unit weight is given by,
\(γ_{sat}=\frac{W_{sat}}{V} = \frac{W_d+W_w}{V}\)
\(γ_{sat}=\frac{(γ_s*V_s + γ_w *V_w)}{V}\)
When V_s = 1, V_w = e and V = 1+e
\(γ_{sat}=\frac{(γ_s*1 + γ_w *e)}{(1+e)} = \frac{(Gγ_w+ γ_w e)}{(1+e)}\)
\(γ_{sat}=\frac{(G+e) γ_w}{(1+e)}\).