The relationship between γ_d, G and e is given by ______
a) γ_d = \(\frac{Gγ_w}{1-e}\)
b) γ_d = \(\frac{G+γ_w}{1+e}\)
c) γ_d = \(\frac{Gγ_w}{1+e}\)
d) γ_d = \(\frac{Gγ_w}{e}\)

Answer: c
Explanation: The dry unit weight is given by,
γ_d = \(\frac{W_d}{V} = \frac{γ_s*V_s}{V}\)
when V_s = 1, we have V = (1+e)
γ_d = γ_s*1/(1+e)
But γ_s = Gγ_w
γ_d = \(\frac{Gγ_w}{1+e}\).