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Find the number of HSFG bolts of diameter 20mm, grade 88 for connection of member carrying factored tensile load of 200kN when no slip is permitted.

a) 5
b) 4
c) 3
d) 2

Answer: b
Explanation: Fo=0.7fubAnb=0.7x800x0.78x(π/4)x202x10-3=137.22 kN
Assume μf=0.5, ne=1, kh=1
Slip resistance of bolt = μf ne kh Fo/1.25 = 0.5x1x1x137.22/1.25 =54.88 kN
Number of bolts required = 200/54.88 = 3.64 = 4(approximately).

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