a) 70.26 kN
b) 109.82 kN
c) 50.18 kN
d) 29.56 kN
Answer: c
Explanation: diameter of bolt = 16mm, diameter of hole =16+2 =18mm
e=1.5×18=27mm, p=2.5×16=40mm
e/3d0 = 27/(3×18) = 0.5, p/3d0 -0.25 = 40/(3×18) -0.25=0.49, fub /fb = 400/410=0.975
kb = minimum of (e/3d0, p/3d0 -0.25, fub /fb,1) = 0.49
bearing strength = 2.5kbdtfu/1.25 = 2.5×0.49x16x8x400x10-3/1.25 = 50.18 kN.
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