1.What is the molecular weight of hydrazine?
a) 28
b) 30
c) 32
d) 17
Explanation:Molecular formula of hydrazine is N2H4. 2 nitrogen atoms and 4 hydrogen atoms make 1 mole of N2H4. Molecular weight = 2*14 + 4*1 = 32.
2. Hydrazine is miscible with water. Is the statement true/false?
a) True
b) False
Explanation: Hydrazine is miscible with water since it mixes in all proportions with water. It is also miscible with low molecular weight alcohols and forms constant boiling mixture with 28.5 weight % water.
3. What is the percentage of N2H4 present in hydrazine hydrate?
a) 64% N2H4
b) 80% N2H4
c) 98% N2H4
d) 50% N2H4
Explanation: Percentage of N2H4 present in hydrazine hydrate is 64% N2H4 whereas 98% N2H4 present in the anhydrous hydrazine produced from the distillation of hydrazine hydrate.
4. The gas produced in the side reaction of ammonia-sodium hypochlorite process is _________
a) H2
b) N2
c) Cl2
d) O2
Explanation:The side reaction of ammonia-sodium hypochlorite process is 2NH2Cl+N2H4 →2NH4Cl+N2, hence the gas produced is nitrogen.
5. Inhibitor used in the formation of chloro amine is ___________
a) Aspirin
b) Nitric oxide
c) Glycol
d) Gelatin
Explanation: Aqueous ammonia reacts with sodium hypochlorite in 3:1 ratio to produce chloro amine and sodium hydroxide in presence of glue or gelatin inhibitor.
6. Which gas is used for shipping anhydrous hydrazine?
a) Nitrogen
b) Nitric oxide
c) Oxygen
d) Chlorine
Explanation: Nitrogen gas is used for shipping anhydrous hydrazine in stainless steel drums. A little bit of Organic inhibitor is added for providing stability.
7. Which of the following compound exists in liquid state?
a) Diborane
b) Pentaborane
c) Decaborane
d) Borane
Explanation: Diborane is a colorless gas. Pentaborane is a colorless liquid. Decaborane is a white solid. Borane is a colorless gas. Borane is also called borine.
8. Which grade hydrogen is used in production of boranes?
a) Zero grade
b) Ultra high purity grade
c) Industrial grade
d) Research grade
Explanation: Industrial grade hydrogen is used in the production of boranes. It reacts with sodium metal to form sodium hydride which is used for producing sodium borohydride.
9. Which of the following reaction is wrong?
a) Na+H →NaH
b) 2B5H9 →B10H14 + 2H2
c) 3CH3OH + H3BO3 →B(OCH3)3 + 3H2O
d) 3NaBH4 + BI3 →2B2H6 + 3NaI
Explanation: 3NaBH4 + BI3 →2B2 H6 + 3NaI is wrong because sodium borohydride can react only with boron tri fluoride or boron tri chloride but not with boron tri iodide or boron tri bromide.
10. 7(i)+ B(OCH3)3 → NaBH4 + 6(ii)+ 3(iii) Name the compounds i, ii, iii?
a) i.sodium hydride ii.sodium iii.methanol
b) i.sodium Ii.methanol iii.sodium hydride
c) i.sodium ii.sodium hydride iii.methanol
d) i.sodium hydride ii.methanol iii.sodium
Explanation: The reaction is 7NaH + B(OCH3)3 → NaBH4 + 6Na + 3CH3OH, hence compound i is sodium hydride, compound ii is sodium and compound iii is methanol.