Chemical Process Calculation Questions and Answers Part-19

1. For the given following reaction
a NH3 + b O2 → c NO2 + d H2O
The value of a, is?
a) 2
b) 4
c) 6
d) 8

Answer: a
Explanation: Balance N, O and H.

2. For the given following reaction
a NH3 + b O2 → c NO2 + d H2O
The value of b, is?
a) 1.5
b) 2.5
c) 3.5
d) 4.5

Answer: c
Explanation: Balance N, O and H.

3. For the given following reaction
a NH3 + b O2 → c NO2 + d H2O
The value of c, is?
a) 2
b) 4
c) 6
d) 8

Answer: a
Explanation: Balance N, O and H.

4. For the given following reaction
a NH3 + b O2 → c NO2 + d H2O
The value of d, is?
a) 1
b) 2
c) 3
d) 4

Answer: c
Explanation: Balance N, O and H.

5. If 1 kg of Octane is oxidised with O2, then how much kg of O2 is required?
a) 200
b) 400
c) 600
d) 800

Answer: b
Explanation: 1 mole of Octane = 12.5 moles of O2.

6. If 1 kg of butane is burned with O2, then how much kg of CO2 will produce by 40 kg of butane?
a) 111.38
b) 121.38
c) 131.38
d) 141.38

Answer: b
Explanation: 1 mole of butane = 4 moles of CO2.

7. For the given chemical reaction
C6H14 + 19/2 O2 → 6 CO2+ 7 H2O
If the required amount of CO2 is 440 kg/hour then how much kg of C6H14 should be burned per hour?
a) 123.33
b) 143.33
c) 163.33
d) 183.33

Answer: b
Explanation: 1 mole of C6H14 = 6 moles of CO2.

8. For the given chemical reaction
C6H14 + 19/2 O2 → 6 CO2+ 7 H2O
If the required amount of water is 72 kg then how much C6H14 should be burned per hour?
a) 49.14
b) 39.14
c) 89.14
d) 29.14

Answer: a
Explanation: 1 mole of C6H14 = 7 moles of H2O

9. For a given chemical reaction
N2 + 3H2 → 2NH3
For producing 34 gms of NH3, how many moles of N2 is required?
a) 1
b) 2
c) 3
d) 4

Answer: a
Explanation: 1 mole of N2 = 2 moles of NH3.

10. For a given chemical reaction
N2 + 3H2 → 2NH3
For producing 34 gms of NH3, how many gms of H2 is required?
a) 3
b) 6
c) 9
d) 12

Answer: b
Explanation: 3 mole of H2 = 2 moles of NH3.