a) \[n=4,l=0,m=0,s=+\frac{1}{2}\]
b) \[n=3,l=0,m=0,s=+\frac{1}{2}\]
c) \[n=3,l=1,m=1,s=+\frac{1}{2}\]
d) \[n=3,l=2,m=1,s=+\frac{1}{2}\]
Answer: d
Explanation: Atomic orbitals are 4s, 3s, 3p and 3d. (n + l) values being
4, 3, 4 and 5. Hence 3d has highest energy.
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