a) π/6
b) π/4
c) π/6
d) 2π/3
Answer: c
Explanation: Consider a unit cell,
Volume of each spherical particle = (π/6)*d3
Total volume of container=1*1*1=1
No. of solids in the container=(1/d)*(1/d)*(1/d)=(1/d3)
Volume of the solids Vs=(π/6)*d3*(1/d3)=(π/6).
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