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The energy of a photon is given as △E╱atom=3.03∗10^−19 J atom^−1. Then the wavelength (λ) of the photon is.

The energy of a photon is given as \[\triangle E\diagup atom = 3.03*10^{-19} J atom^{-1}\]     . Then the wavelength \[\left(\lambda\right)\] of the photon is.
a) 65.6 nm
b) 656 nm
c) 0.656 nm
d) 6.56 nm

Answer: b

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