Joule- Thomson coefficient \[\left(\frac{\delta T}{\delta P}\right)_{H}\] for an ideal gas is
a) zero
b) positive
c) negative
d) None of these
Answer: a
Explanation: Ideal gas does not exhibit Joule Thomson effect. Hence \[\left(\frac{\delta T}{\delta P}\right)_{H}\] , the Joule-Thomson coefficient is zero
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