From two places, 60 km apart, A and B start towards each other at the same time and meet each other after 6 hour. If A traveled with $$\frac{2}{3}$$ of his speed and B traveled with double of his speed, they would have met after 5 hours. The speed of A is:
a) 4 km/h
b) 6 km/h
c) 10 km/h
d) 12 km/h
Answer: b
Explanation: A →_______60Km_________← B
Let the speed of A = x kmph and that of B = y kmph
x × 6 + y × 6 = 60
x + y = 10 ——— (i)
$$\left( {\frac{{2{\text{x}}}}{3} \times 5} \right) + \left( {2{\text{y}} \times 5} \right) = 60$$
10x + 30y = 180
x + 3y = 18 ———- (ii)
From equation (i) × 3 – (ii)
3x + 3y – x – 3y = 30 – 18
2x = 12
x = 6 kmph
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