1. What will be the final value of j in the following C code?
#include <stdio.h>
int main()
{
int i = 10, j = 0;
if (i || (j = i + 10))
//do something
;
}
a) 0
b) 20
c) Compile time error
d) Depends on language standard
Discussion
2. What will be the output of the following C code?
#include <stdio.h>
int main()
{
int i = 1;
if (i++ && (i == 1))
printf("Yes\n");
else
printf("No\n");
}
a) Yes
b) No
c) Depends on the compiler
d) Depends on the standard
Discussion
3. function tolower(c) defined in library <ctype.h> works for ___________
a) Ascii character set
b) Unicode character set
c) Ascii and utf-8 but not EBCDIC character set
d) Any character set
Discussion
4. What will be the output of the following C code considering the size of a short int is 2, char is 1 and int is 4 bytes?
#include <stdio.h>
int main()
{
short int i = 20;
char c = 97;
printf("%d, %d, %d\n", sizeof(i), sizeof(c), sizeof(c + i));
return 0;
}
a) 2, 1, 2
b) 2, 1, 1
c) 2, 1, 4
d) 2, 2, 8
Discussion
5. Which type of conversion is NOT accepted?
a) From char to int
b) From float to char pointer
c) From negative int to char
d) From double to char
Discussion
Explanation: Conversion of a float to pointer type is not allowed
6. What will be the data type of the result of the following operation?
(float)a * (int)b / (long)c * (double)d
a) int
b) long
c) float
d) double
Discussion
7. Which of the following type-casting have chances for wrap around?
a) From int to float
b) From int to char
c) From char to short
d) From char to int
Discussion
8. Which of the following typecasting is accepted by C?
a) Widening conversions
b) Narrowing conversions
c) Widening & Narrowing conversions
d) None of the mentioned
Discussion
9. When do you need to use type-conversions?
a) The value to be stored is beyond the max limit
b) The value to be stored is in a form not supported by that data type
c) To reduce the memory in use, relevant to the value
d) All of the mentioned
Discussion
10. What will be the output of the following C code?
#include <stdio.h>
int main()
{
int i = 0;
int x = i++, y = ++i;
printf("%d % d\n", x, y);
return 0;
}
a) 0, 2
b) 0, 1
c) 1, 2
d) Undefined
Discussion