Transportation Engineering Questions and Answers Part-26

1. Equivalent flow rate is calculated by which of the following?
a) vp = V/(PHF x N x fhv x fp)
b) vp = V x (PHF x N x fhv x fp)
c) vp = V/(PHF + N x fhv x fp)
d) vp = V/(PHF x N + fhv x fp)

Answer: a
Explanation: Equivalent flow rate is calculated using vp = V/(PHF x N x fhv x fp). Here, vp = equivalent flow rate, V = directional hourly volume, PHF = peak hour factor, N = number of lanes in one direction, fhv= heavy vehicle adjustment factor, and fp = driver population adjustment factor.

2. Vehicles which doesn’t change lanes in the weaving section causes inconvenience in traffic stream?
a) True
b) False

Answer: b
Explanation: “Vehicles which doesn’t change lanes in the weaving section causes inconvenience in traffic stream” is an incorrect statement. The correct statement is, “Vehicles which change lanes in the weaving section causes inconvenience in traffic stream”. Hence weaving sections become the bottleneck of the road system.

3. What is weaving capacity?
a) The maximum number of vehicles per hour that can cross a weaving section in a period of time
b) The minimum number of vehicles per hour that can cross a weaving section in a period of time
c) The maximum number of vehicles per day that can cross a weaving section in a period of time
d) The minimum number of vehicles per day that can cross a weaving section in a period of time

Answer: c
Explanation: Weaving capacity is the maximum number of vehicles per hour that can cross a weaving section in a period of time. It is also defined as the no. of lane change operations within the given weaving section.

4. Weaving capacity is affected by which prime factor given below?
a) Length of weaving section
b) Driver characteristics
c) Traffic police
d) Traffic control devices

Answer: a
Explanation: Weaving capacity is affected by the length of the weaving section. In Type A configurations (in Highway Capacity Manual, 2000) there appears to be a great sensitivity to length and Type B and C sections show little difference in the capacity of the section.

5. Higher capacity value occurs when free-flow speeds are ______
a) Higher
b) Low
c) 30 kmph
d) 60 kmph

Answer: a
Explanation: According to Highway Capacity Manual (2000), Higher capacity value occurs when free-flow speeds are higher. Weaving capacity is affected by the length and width of the weaving section.

6. Which of the following is a limitation of a rotary?
a) Rotaries are self-governing
b) Rotaries require a large area
c) Eliminates severe conflicts
d) Accidents are less

Answer: b
Explanation: Rotaries require large area hence they are a costly affair in urban areas. The advantages of rotary is that they are self-governing, eliminates severe conflicts and accidents.

7. How many traffic operations are there in a rotary?
a) 1
b) 2
c) 3
d) 4

Answer: c
Explanation: There are 3 traffic operations in a rotary and they are diverging, merging and weaving. Diverging is a traffic operation when the vehicles moving in one direction parts into different directions according to their destinations. Merging is the opposite of diverging and weaving is a combination of both.

8. The capacity of rotary is found out by the capacity of each weaving section.
a) True
b) False

Answer: a
Explanation: The statement, “The capacity of rotary is found out by the capacity of each weaving section” is true. The minimum of the capacity of all the weaving section is the capacity of rotary.

9. Which one of the following is the empirical formula to find the capacity of the weaving section?
a) Qw = (280w(1+e/w)(1-p/3))/(1+w/l)
b) Qw = (280w(1+e/w)(1-p/3))/(1-w/l)
c) Qw = (280w(1-e/w)(1-p/3))/(1+w/l)
d) Qw = (280w(1+e/w)(1*p/3))/(1+w/l)

Answer: a
Explanation: Qw = (280w(1+e/w)(1-p/3))/(1+w/l) is the empirical formula to find the capacity of the weaving section. Here, Qw = capacity of weaving section, w = weaving width, l = length of weaving, p = proportion of weaving traffic to the non-weaving traffic.

10. The capacity formula is valid only if the weaving width is between _______
a) 6 and 18 metres
b) 1 and 10 metres
c) 3 and 9 metres
d) 4 and 14 metres

Answer: a
Explanation: The capacity formula is valid only if the weaving width is between 6 and 18 metres.