Basic Chemical Engineering Questions and Answers Part-19

1. In a steady-state reactive system, 1 molar each of NaOH and HCl are supplied to the system both at the rate of 100 L/min, then what is the amount of NaCl produced?
a) 1 molar
b) 2 molar
c) 3 molar
d) 4 molar

Answer: a
Explanation:The balanced reaction of the system is NaOH + HCl -> NaCl + H2O, => amount of NaCl = amount of HCl = amount of NaOH = 1 molar.

2. In a steady-state reactive system, NaCl and H2CO3 are supplied to the system at the rate of 200 L/min and 100 L/min respectively, what is the rate at which Na2CO3 is produced?
a) 100 L/min
b) 200 L/min
c) 300 L/min
d) 400 L/min

Answer: c
Explanation: As the system is in steady state, => rate of product = rate of feed, => rate of Na2CO3 = 200 + 100 = 300 L/min.

3. In a steady-state reactive system, 2 molar NaCl and 1 molar H2CO3 are supplied to the system both at the rate of 100 mole/min, then how much Na2CO3 produced?
a) 1 molar
b) 2 molar
c) 3 molar
d) 4 molar

Answer: a
Explanation: The balanced reaction of the system is 2NaCl + H2CO3 -> Na2CO3 + 2HCl, => amount of Na2CO3 = 1 molar.

4. In a steady-state reactive system, 5 molar CH4 and 5 molar O2 are supplied to the system, then what is the amount of CO2 produced?
a) 2.5 molar
b) 5 molar
c) 7.5 molar
d) 10 molar

Answer: b
Explanation: The balanced chemical reaction of the system is CH4 + O2 -> CO2 + 2H2O, => amount of CO2 = 5 molar.

5. In a steady-state reactive system, 5 molar KNO3 and 5 molar H2SO4 are supplied to the system, then what is the amount of K2SO4 produced?
a) 2.5 molar
b) 5 molar
c) 7.5 molar
d) 10 molar

Answer: a
Explanation: The balanced chemical reaction of the system is 2KNO3 + H2SO4 -> K2SO4 + 2HNO3, => amount of K2SO4 = 2.5 molar.

6. The flow in rate of HCl and NaOH in a system are 1 mole/hr each what is the flow out rate of NaCl?
a) 1 mole/hr
b) 2 mole/hr
c) 3 mole/hr
d) 4 mole/hr

Answer: a
Explanation: The reaction is HCl + NaOH -> NaCl + H2O, => flow out rate of NaCl = 1 mole/hr.

7. The flow in rate of H2SO4 and NaCl in a system are 2 mole/hr each what is the flow out rate of HCl?
a) 1 mole/hr
b) 2 mole/hr
c) 3 mole/hr
d) 4 mole/hr

Answer: b
Explanation: The reaction is H2SO4 + 2NaCl -> 2HCl + Na2SO4, => flow out rate of HCl = 2*1 = 2 mole/hr.

8. The flow in rate of CH4 and O2 in a system are 2 mole/hr each what is the flow out rate of CO2?
a) 1 mole/hr
b) 2 mole/hr
c) 3 mole/hr
d) 4 mole/hr

Answer: a
Explanation: The reaction is CH4 + 2O2 -> CO2 + 2H2O, => flow out rate of CO2 = 1*1 = 1 mole/hr.

9. The flow in rate of C3H8 and O2 in a system are 2 mole/hr each what is the flow out rate of CO2?
a) 1 mole/hr
b) 1.2 mole/hr
c) 1.5 mole/hr
d) 2 mole/hr

Answer: b
Explanation: The reaction is C3H8 + 5O2 -> 3CO2 + 4H2O, => flow out rate of CO2 = 2*3/5 = 1.2 mole/hr.

10. The flow in rate of C6H6 and H2 in a system are 3 mole/hr each what is the flow out rate of C6H12
a) 1 mole/hr
b) 1.2 mole/hr
c) 1.5 mole/hr
d) 2 mole/hr

Answer: a
Explanation: The reaction is C6H6 + 3H2 -> C6H12, => flow out rate of C6H12 = 3*1/3 = 1 mole/hr.