Molecular Biology Questions and Answers Part-8

1. What is the condition required to observe B form of DNA?
a) Low humidity
b) High humidity
c) Low temperature
d) High temperature

Answer: b
Explanation: X – ray diffraction studies of DNA shows two different kinds of structures of DNA, A and B forms. Of the two, B form of DNA is generally observable at high humidity and closely resembles to the structure of the DNA in physiological condition.

2. What is the condition required to observe A form of DNA?
a) Low humidity
b) High humidity
c) Low temperature
d) High temperature

Answer: a
Explanation: A form of DNA is generally observed at low humidity. The conformation is usually taken by DNA – RNA and RNA – RNA complexes. They have a much more compact structure than any another form of DNA.

3. How many bases are there in per turn of the B form of DNA?
a) 8 bp
b) 9 bp
c) 10 bp
d) 11 bp

Answer: c
Explanation: B form of DNA has 10 base pairs per turn. The height of one complete turn, that is, the pitch is 2.46 nm.

4. Which of the following is not a character of A DNA?
a) Short and broad
b) Left handed helix
c) Narrow minor groove
d) Broad and shallow major groove

Answer: b
Explanation: A form of DNA is known to have a right handed helical structure. The left handed helical conformation is the characteristic form of the Z form of DNA.

5. How many bases are there in per turn of the A form of DNA?
a) 11 bp
b) 10 bp
c) 12 bp
d) 8 bp

Answer: a
Explanation: A form of DNA has 11 base pairs per turn. The height of one complete turn, that is, the pitch is 3.32 nm.

6. Which of the following is not a character of B form of DNA?
a) Longer and thinner
b) Right-handed helix
c) Narrow minor groove
d) Flat major groove

Answer: d
Explanation: B form of DNA has a wide and intermediate major groove. Flattened major groove is normally found Z form of DNA.

7. In a right handed DNA the glycosidic bond is in syn configuration
a) true
b) false

Answer: b
Explanation: Glycosidic bond connects the base to the 1’ position of 2’-deoxyribose. This bond can be in one of the two conformations called syn and anti. In right handed DNA, the glycosidic bond is always in the anti configuration.

8. In the Z form of DNA the fundamental repeating unit is __________
a) Purine – pyrimidine nucleotide
b) Purine – pyrimidine dinucleotide
c) Purine – pyrimidine tri-nucleotide
d) Purine – pyrimidine tetra-nucleotide

Answer: d
Explanation: As we know Z form of DNA is the left–handed DNA. Thus it has the anti–conformation at the pyrimidine and the syn–conformation at the purine and is usually a dinucleotide unit.

9. What is the factor responsible for the left-handed helical conformation in Z form of DNA?
a) Syn conformation at pyrimidine
b) Anti conformation at pyrimidine
c) Syn conformation at purine
d) Anti conformation at purine

Answer: c
Explanation: It is the syn conformation at the purine nucleotides that is responsible for the left-handed helical conformation. The change to the syn position in the purine residues to alternating anti – syn conformation gives the backbone of the left-handed DNA a zig-zag look.

10. In higher salt concentration the DNA helix assumes the right-handed conformation.
a) true
b) false

Answer: b
Explanation: In higher salt concentration the DNA helix assumes the left-handed conformation. This is because the higher concentration of the positively charged ions is required to shield the negatively charged phosphate groups to maintain the stability of the conformation.