a) O(m)
b) O(n)
c) O(m*n)
d) Data is insufficient
Answer: a
Explanation: To perform deQueue operation you need to pop each element from the first stack and push it into the second stack. In this case you need to pop ‘m’ times and need to perform push operations also ‘m’ times. Then you pop the first element from this second stack (constant time) and pass all the elements to the first stack (as done in the beginning)(‘m-1’ times). Therfore the time complexity is O(m).
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What is the output of the given code?
counter=1
if counter<=5
puts (counter)
counter=counter+1What is the output of the given code?
if(a==10 && b=9)
print “true”
else
print “false”
endWhich of the following are used for comparison?
What is the output of the given code?
a=10
b=9
if(a>b)
print (“a greater than b”)
else
print “Not greater”
endAssignment operator is also known as relational operator.
What is the output of the given code?
a=”string”
b=”strings”
if(a==b)
print (“a and b are same”)
else
print “Not same”
endWhat is the output of the given code?
test_1 = 17 > 16
puts(test_1)
test_2 = 21 <= 30
puts(test_2)
test_3 = 9 >= 9
puts(test_3)
test_4 = -11 > 4
puts(test_4)
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