What will be the output of the following Python code?
l=list(‘HELLO’)
p=l[0], l[-1], l[1:3]
‘a={0}, b={1}, c={2}’.format(*p)
a) Error
b) “a=’H’, b=’O’, c=(E, L)”
c) “a=H, b=O, c=[‘E’, ‘L’]”
d) Junk value

Answer: c
Explanation: In the code shown above, the value for a is substituted by l[0], that is ‘H’, the value of b is substituted by l[-1], that is ‘O’ and the value for c is substituted by l[1:3]. Here the use of *p is to unpack a tuple items into individual function arguments.