What will be the output of the following Java program?class Output{static void main(String args[]){int x , y = 1;x = 10;if(x != 10 && x / 0 == 0)System.out.println(y);elseSystem.out.println(++y);}}

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What will be the output of the following Java program?
class Output
{
static void main(String args[])
{
int x , y = 1;
x = 10;
if(x != 10 && x / 0 == 0)
System.out.println(y);
else
System.out.println(++y);
}
}

What will be the output of the following Java program?
class Output
{
static void main(String args[])
{
int x , y = 1;
x = 10;
if(x != 10 && x / 0 == 0)
System.out.println(y);
else
System.out.println(++y);
}
}
a) 1
b) 2
c) Runtime Error
d) Compilation Error

Answer: d
Explanation: main() method must be made public. Without main() being public java run time system will not be able to access main() and will not be able to execute the code.

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What will be the output of the following Java program?class Output{static void main(String args[]){int x , y = 1;x = 10;if(x != 10 && x / 0 == 0)System.out.println(y);elseSystem.out.println(++y);}}

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What will be the output of the following Java program?
class Output
{
static void main(String args[])
{
int x , y = 1;
x = 10;
if(x != 10 && x / 0 == 0)
System.out.println(y);
else
System.out.println(++y);
}
}