What will be the output of the following Java program?
class exception_handling
{
public static void main(String args[])
{
try
{
int a[] = {1, 2,3 , 4, 5};
for (int i = 0; i < 5; ++i)
System.out.print(a[i]);
int x = 1/0;
}
catch(ArrayIndexOutOfBoundsException e)
{
System.out.print(“A”);
}
catch(ArithmeticException e)
{
System.out.print(“B”);
}
}
}
a) 12345
b) 12345A
c) 12345B
d) Compilation Error

Answer: c
Explanation: There can be more than one catch of a single try block. Here Arithmetic exception occurs instead of Array index out of bound exception hence B is printed after 12345
Output:
12345B