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What will be the output of the following Java code?
class Output
{
public static void main(String args[])
{
Double y = new Double(257.57812);
Double i = new Double(257.578123456789);
try
{
int x = i.compareTo(y);
System.out.print(x);
}
catch(ClassCastException e)
{
System.out.print(“Exception”);
}
}
}

What will be the output of the following Java code?
class Output
{
public static void main(String args[])
{
Double y = new Double(257.57812);
Double i = new Double(257.578123456789);
try
{
int x = i.compareTo(y);
System.out.print(x);
}
catch(ClassCastException e)
{
System.out.print(“Exception”);
}
}
}
a) 0
b) 1
c) Exception
d) None of the mentioned

Answer: b
Explanation: i.compareTo() methods two double values, if they are equal then 0 is returned and if not equal then 1 is returned, here 257.57812 and 257.578123456789 are not equal hence 1 is returned and stored in x.
Output:
1

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