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What will be the output of the following C# code?
static void Main(string[] args)
{
int[] arr = new int[] {1, 2, 3, 4, 5};
fun1(ref arr);
Console.ReadLine();
}
static void fun1(ref int[] array)
{
for (int i = 0; i < array.Length; i++)
{
array[i] = array[i] + 5;
Console.WriteLine(array[i] + ” “);
}
}

What will be the output of the following C# code?
static void Main(string[] args)
{
int[] arr = new int[] {1, 2, 3, 4, 5};
fun1(ref arr);
Console.ReadLine();
}
static void fun1(ref int[] array)
{
for (int i = 0; i < array.Length; i++)
{
array[i] = array[i] + 5;
Console.WriteLine(array[i] + ” “);
}
}
a) 6 7 8 9 10
b) 15 17 8 8 20
c) 15 17 8 29 20
d) Syntax error while passing reference of array variable

Answer: a
Explanation: array ‘arr’ after declaration is passed as reference parameter.
a[0] = 1 + 5 = 6.
a[1] = 2 + 5 = 7.
.
.
a[4] = 5 + 5 = 10.
Output :
15 17 8 29 20

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