What will be the output of the following C code?
#include < stdio.h >
int i;
int main()
{
extern int i;
if (i == 0)
printf(“scope rules\n”);
}
a) scope rules
b) Compile time error due to multiple declaration
c) Compile time error due to not defining type in statement extern i
d) Nothing will be printed as value of i is not zero because i is an automatic variable
Answer: a
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What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int main()
{
char *ptr;
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ptr = Str;
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}What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int main()
{
char arr[20];
int i;
for(i = 0; i < 10; i++)
*(arr + i) = 65 + i;
*(arr + i) = ‘\0’;
cout << arr;
return(0);
}
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