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What will be the output of the following C code?
#include < stdio.h >
int foo(int, int);
#define foo(x, y) x / y + x
int main()
{
int i = -6, j = 3;
printf(“%d “,foo(i + j, 3));
#undef foo
printf(“%d\n”,foo(i + j, 3));
}
int foo(int x, int y)
{
return x / y + x;
}

What will be the output of the following C code?
#include < stdio.h >
int foo(int, int);
#define foo(x, y) x / y + x
int main()
{
int i = -6, j = 3;
printf(“%d “,foo(i + j, 3));
#undef foo
printf(“%d\n”,foo(i + j, 3));
}
int foo(int x, int y)
{
return x / y + x;
}
a) -8 -4
b) Compile time error
c) -8 -8
d) Undefined behaviour

Answer: a

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