What will be the output of the following C++ code?#include <iostream>using namespace std;int main(){int a = 5, b = 6, c, d;c = a, b;d = (a, b);cout << c << ' ' << d;return 0;}

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What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int main()
{
int a = 5, b = 6, c, d;
c = a, b;
d = (a, b);
cout << c << ‘ ‘ << d;
return 0;
}

What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int main()
{
int a = 5, b = 6, c, d;
c = a, b;
d = (a, b);
cout << c << ' ' << d;
return 0;
}
a) 5 6
b) 6 5
c) 6 7
d) 6 8

Answer: a
Explanation: It is a separator here. In C, the value a is stored in c and in d the value b is stored in d because of the bracket.
Output:
5 6

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What will be the output of the following C++ code?#include <iostream>using namespace std;int main(){int a = 5, b = 6, c, d;c = a, b;d = (a, b);cout << c << ‘ ‘ << d;return 0;}

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What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int main()
{
int a = 5, b = 6, c, d;
c = a, b;
d = (a, b);
cout << c << ‘ ‘ << d;
return 0;
}