What will be the output of the following C++ code?#include <iostream>using namespace std;int fun(int=0, int = 0);int main(){cout << fun(5);return 0;}int fun(int x, int y) { return (x+y); }

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What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int fun(int=0, int = 0);
int main()
{
cout << fun(5);
return 0;
}
int fun(int x, int y) { return (x+y); }

What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int fun(int=0, int = 0);
int main()
{
cout << fun(5);
return 0;
}
int fun(int x, int y) { return (x+y); }
a) -5
b) 0
c) 10
d) 5

Answer: d
Explanation: C++ allows to define such prototype of the function in which you are not required to give variable names only the default values. While in function definition you can provide the variable names corresponding to each parameter.

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What will be the output of the following C++ code?#include <iostream>using namespace std;int fun(int=0, int = 0);int main(){cout << fun(5);return 0;}int fun(int x, int y) { return (x+y); }

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What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int fun(int=0, int = 0);
int main()
{
cout << fun(5);
return 0;
}
int fun(int x, int y) { return (x+y); }