What will be the output of the following C++ code?#include <iostream>using namespace std;int add(int a, int b);int main(){int i = 5, j = 6;cout << add(i, j) << endl;return 0;}int add(int a, int b ){int sum = a + b;a = 7;return a + b;}

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What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int add(int a, int b);
int main()
{
int i = 5, j = 6;
cout << add(i, j) << endl;
return 0;
}
int add(int a, int b )
{
int sum = a + b;
a = 7;
return a + b;
}

What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int add(int a, int b);
int main()
{
int i = 5, j = 6;
cout << add(i, j) << endl;
return 0;
}
int add(int a, int b )
{
int sum = a + b;
a = 7;
return a + b;
}
a) 11
b) 12
c) 13
d) compile time error

Answer: c
Explanation: The value of a has been changed to 7, So it returns as 13.
Output:
13

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What will be the output of the following C++ code?#include <iostream>using namespace std;int add(int a, int b);int main(){int i = 5, j = 6;cout << add(i, j) << endl;return 0;}int add(int a, int b ){int sum = a + b;a = 7;return a + b;}

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What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int add(int a, int b);
int main()
{
int i = 5, j = 6;
cout << add(i, j) << endl;
return 0;
}
int add(int a, int b )
{
int sum = a + b;
a = 7;
return a + b;
}