What will be the output of the following C++ code?#include <iostream>class Test{public:void fun();};static void Test::fun(){std::cout<<"fun() is static";}int main(){Test::fun();return 0;}

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What will be the output of the following C++ code?
#include <iostream>
class Test
{
public:
void fun();
};
static void Test::fun()
{
std::cout<<“fun() is static”;
}
int main()
{
Test::fun();
return 0;
}

What will be the output of the following C++ code?
#include <iostream>
class Test
{
public:
void fun();
};
static void Test::fun()
{
std::cout<<“fun() is static”;
}
int main()
{
Test::fun();
return 0;
}
a) fun() is static
b) Compile-time Error
c) Run-time Error
d) Nothing is printed

Answer: b
Explanation: The prototype of the functions are not matched. The function declared inside a class does not have static linkage however the class defined outside the class has the static linkage, therefore, the program gives an error.

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What will be the output of the following C++ code?#include <iostream>class Test{public:void fun();};static void Test::fun(){std::cout<<“fun() is static”;}int main(){Test::fun();return 0;}

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What will be the output of the following C++ code?
#include <iostream>
class Test
{
public:
void fun();
};
static void Test::fun()
{
std::cout<<“fun() is static”;
}
int main()
{
Test::fun();
return 0;
}