a) \(\frac{dθ}{dt}\) = KA (θ-θ0)
b) \(\frac{dθ}{dt}\) = KA (θ+θ0)
c) \(\frac{dθ}{dt}\) = KA (θ*θ0)
d) \(\frac{dθ}{dt}\) = KA (θ/θ0)
Answer: a
Explanation: Newton’s law of cooling states that, the rate of heat radiated or lost by a body is directly proportional to the excess temperature, provided that the excess temperature is less as compared to the surrounding temperature.
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