What does the following function do for a given Linked List with first node as head?
void fun1(struct node* head)
{
if(head == NULL)
return;
fun1(head->next);
printf(“%d “, head->data);
}
a) Prints all nodes of linked lists
b) Prints all nodes of linked list in reverse order
c) Prints alternate nodes of Linked List
d) Prints alternate nodes in reverse order
Answer: b
Explanation: fun1() prints the given Linked List in reverse manner.
For Linked List 1->2->3->4->5, fun1() prints 5->4->3->2->1.
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What is the output of the given code?
counter=1
if counter<=5
puts (counter)
counter=counter+1What is the output of the given code?
if(a==10 && b=9)
print “true”
else
print “false”
endWhich of the following are used for comparison?
What is the output of the given code?
a=10
b=9
if(a>b)
print (“a greater than b”)
else
print “Not greater”
endAssignment operator is also known as relational operator.
What is the output of the given code?
a=”string”
b=”strings”
if(a==b)
print (“a and b are same”)
else
print “Not same”
endWhat is the output of the given code?
test_1 = 17 > 16
puts(test_1)
test_2 = 21 <= 30
puts(test_2)
test_3 = 9 >= 9
puts(test_3)
test_4 = -11 > 4
puts(test_4)
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