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Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

a) 39, 30
b) 41, 32
c) 42, 33
d) 43, 34

Answer: c
Explanain : Let their marks be (x + 9) and x
$$\eqalign{ & x + 9 = \frac{{56}}{{100}}\left( {x + 9 + x} \right) \cr & 25\left( {x + 9} \right) = 14\left( {2x + 9} \right) \cr & 3x = 99 \cr & x = 33 \cr} $$
So, their marks are 42 and 33

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