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There is a tree between houses of A and B. If the tree leans on A’s House, the tree top rests on his window which is 12 m from ground. If the tree leans on B’s House, the tree top rests on his window which is 9 m from ground. If the height of the tree is 15 m, what is distance between A’s and B’s house?

a) 21 m
b) 25 m
c) 16 m
d) 12 m

Answer: a
Explanation:
q7
In $$\Delta $$STR, by Pythagoras theorem
$$\eqalign{ & R{T^2} = S{T^2} + R{S^2} \cr & S{T^2} = {15^2} – {9^2} = 144 \cr & ST = 12\,{\text{m}} \cr} $$
In $$\Delta $$TQP, by Pythagoras theorem
$$\eqalign{ & P{T^2} = T{Q^2} + P{Q^2} \cr & T{Q^2} = {15^2} – {12^2} = 81 \cr & TQ = 9\,{\text{m}} \cr} $$
Distance between houses
SQ = ST + TQ
SQ = 12 + 9
SQ = 21 m

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