The width of belt is 15 cm and maximum tension per cm width is not to exceed 12 kg. T₁/T₂=2.25. Diameter of driver=1m and it makes 220 rpm. Find the horse power that can be transmitted.
a) 11.35 HP
b) 10.23 HP
c) 12.12 HP
d) 9.86 HP

Answer: b
Explanation: Maximum tension = 12 * 15 = 180kg
We know that
T = T₁ + T_C = 180
And, T_c = T/3
T_c = 180/3 = 60 kg
T₁ = T-T_c = 180 – 60 = 120kg
T₂ = T₁/2.5 = 120/2.25 = 53.33 kg
P = (T₁-T₂) v = (T₁ – T₂) * 2π Nr
P = (120 – 53.33) * 2\pi * \(\frac{220}{75*60}*\frac{1}{2} \)
P = 10.23 HP.