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The sum of the digits of two-digit number is 10, while when the digits are reversed, the number decrease by 54. Find the changed number.

a) 28
b) 19
c) 37
d) 46

Answer: a
Explanation: Let number be (10x + y)
According to question,
(10x + y) – (10y + x) = 54
10x – 10y + y – x = 54
9x – 9y = 54
x – y = 6 ——-(i)
Sum of digits,
(x + y) = 10 ——- (ii)
(i) – (ii)
So, x – y – x – y = 6 – 10
-2y = -4
y = 2 and, x = 8
Then, the required number is
= (10y + x)
= 10 × 2 + 8
= 28

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