a) 1020
b) 1022
c) 1024
d) 1040
Answer: b
Explanation: First of all,we find the LCM of 4, 6, 10 and 15
LCM of 4, 6, 10, 10 = 60
The smallest four digit no. is 1000. We divide it by 60
$$\frac{{1000}}{{60}}$$ It leaves remainder 40
Now, the smallest four digit no which is divisible by 4, 6, 10, 15 is,
1000 + (60 – 40) = 1020
Required number (as it gives remainder 2 always) would be = 1020 + 2 = 1022
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