a) Available
b) Need
c) Allocation
d) All of the mentioned
Answer: d
Explanation: All of the mentioned
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#include <stdio.h>
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{
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printf(“%d\n”, z);
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#include <stdio.h>
int main()
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int x = 1, y = 2;
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#include <stdio.h>
int main()
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int z = y +(y = 10);
printf(“%d\n”, z);
}What will be the output of the following C code?
#include <stdio.h>
int main()
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int x = 2, y = 0, l;
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z = y = 1, l = x && y;
printf(“%d\n”, l);
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}What will be the output of the following C code?
#include <stdio.h>
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int x = 2, y = 0;
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z = (y++, y);
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#include <stdio.h>
int main()
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