a) $$52\frac{1}{3}$$
b) $$52\frac{1}{2}$$
c) $$52\frac{2}{3}$$
d) None of these
Answer: c
Explanation: Sum of the weights of the students after replacement
= [(52 × 45) – (48 × 5) + (54 × 5)] kg
= 2370 kg
New average
= $$\left( {\frac{{2370}}{{45}}} \right)$$ kg
= $$52\frac{2}{3}$$ kg
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