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The average of the first five multiples of 9 is:

a) 20
b) 27
c) 28
d) 30

Answer: b
Explanation:
$$\eqalign{ & {\text{Required}}\,{\text{average}} \cr & = {\frac{{{\text{total}}\,{\text{sum}}\,{\text{of}}\,{\text{multiple}}\,{\text{of}}\,9}}{5}} \cr & = {\frac{{9 + 18 + 27 + 36 + 45}}{5}} \cr & = 27 \cr} $$
Average of 9 and 45 is also 27.
And average of 18 and 36 is also 27.

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