a) 25 $$\sqrt 3 $$
b) 50 $$\sqrt 3 $$
c) 75 $$\sqrt 3 $$
d) 150
Answer: c
Explanation: AB is a tower and AB = 75 m
From A, the angle of depression of a car C
on the ground is 30°
$$\eqalign{
& {\text{Let distance }}BC = x \cr
& {\text{Now in right }}\Delta ACB, \cr
& \tan \theta = \frac{{AB}}{{BC}} \cr
& \Rightarrow \tan {30^ \circ } = \frac{{75}}{x} \cr
& \frac{1}{{\sqrt 3 }} = \frac{{75}}{x} \cr
& x = 75\sqrt 3 \,m \cr
& BC = 75\sqrt 3 \,m \cr} $$
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