a) 50 $$\sqrt 3 $$
b) 150 $$\sqrt 3 $$
c) 100 $$\sqrt 3 $$
d) 75
Answer: b
Explanation: Let AB be the tower of height 150 m
C is car and angle of depression is 30°
Therefore, ∠ACB = 30° (alternate angle)
In right – angled triangle ABC,
$$\eqalign{
& \frac{{BC}}{{AB}} = \cot {30^ \circ } \cr
& \frac{{BC}}{{150}} = \sqrt 3 \cr
& BC = 150\sqrt 3 \,m \cr} $$
That is, distance of the car from the tower is $$150\sqrt 3 \,m$$
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