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Ravi and Ajay start simultaneously from a place A towards B 60 km apart. Ravi’s speed is 4km/h less than that of Ajay. Ajay, after reaching B, turns back and meets Ravi at a places 12 km away from B. Ravi’s speed is:

a) 12 km/h
b) 10 km/h
c) 8 km/h
d) 6 km/h

Answer: c
Explanation:
Ajay → (x + 4) kmph.
A ________ 60 km _________ B
Ravi → x kmph.
Let the speed of Ravi be x kmph;
Hence, Ajay’s speed = (x + 4) kmph;
Distance covered by Ajay = 60 + 12 = 72 km;
Distance covered by Ravi = 60 – 12 = 48 km.
$$\eqalign{ & \frac{{72}}{{x + 4}} = \frac{{48}}{x} \cr & \frac{3}{{x + 4}} = \frac{2}{x} \cr & 3x = 2x + 8 \cr & x = 8\,{\text{kmph}} \cr} $$

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