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In a kilometre race, A, B and C are three participants. A can give B start of 50 m and C a start of 69 m. The start which B can allow C, is –

a) 17 m
b) 18 m
c) 19 m
d) 20 m

Answer: d
Explanation: A : B : C
= 1000 : (1000 – 50) : (1000 – 69)
= 1000 : 950 : 931
In a 950 m race, B can give C a start of
(950 – 931) m
= 19 m
In a 1000 m race, B can give C a start of
= $$\left( {\frac{{19}}{{950}} \times 1000} \right)$$
= 20 m

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