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In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C:

a) 8 points
b) 10 points
c) 14 points
d) 40 points

Answer: b
Explanation:
$$\eqalign{ & A:B = 100:80 \cr & A:C = 100:72 \cr & \frac{B}{C} = {\frac{B}{A} \times \frac{A}{C}} = {\frac{{80}}{{100}} \times \frac{{100}}{{72}}} \cr & = \frac{{10}}{9} = \frac{{100}}{{90}} = 100:90 \cr & {\text{B}}\,{\text{can}}\,{\text{give}}\,{\text{C}}\,{\text{10}}\,{\text{points}} \cr} $$

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