a) 18 m
b) 20 m
c) 27 m
d) 9 m
Answer: b
Explanation:
$$\eqalign{
& A:B = 100:90 \cr
& A:C = 100:72 \cr
& B:C = {B \over A} \times {A \over C} = {{90} \over {100}} \times {{100} \over {72}} = {{90} \over {72}} \cr} $$
When B runs 90 m, C runs 72 m.
When B runs 100m, C run
$$\left( {{{72} \over {90}} \times 100} \right)m = 80\,m$$
B can give C 20 m
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