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If x + y + z = 0, then x^3 + y^3 + z^3 is equal to :

If x + y + z = 0, then x3 + y3 + z3 is equal to :
a) 0
b) 3xyz
c) $$\frac{{{\text{xy}} + {\text{yz}} + {\text{zx}}}}{{{\text{xyz}}}}$$
d) xyz(xy + yz + zx)

Answer: b
Explanation:

x + y + z = 0
Cubing both side,
(x + y + z)3 = 0
x3 + y3 + z3 – 3xyz = 0 [using formula]
x3 + y3 + z3 = 3xyz

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