a) 2 : 1
b) 3 : 1
c) 3 : 2
d) 21 : 1
Answer: b
Explanation:
$$\eqalign{
& = \frac{x}{y} = \frac{3}{4} \cr
& = \frac{{2x + 3y}}{{3y – 2x}} \cr
& = \frac{{2\left( {\frac{x}{y}} \right) + 3}}{{3 – 2\left( {\frac{x}{y}} \right)}} \cr
& = \frac{{2 \times \frac{3}{4} + 3}}{{3 – 2 \times \frac{3}{4}}} \cr
& = \frac{9}{2} \times \frac{2}{3} = 3 \cr
& = \left( {2x + 3y} \right):\left( {3y – 2x} \right) \cr
& = 3:1 \cr} $$
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